阅读(3340) (0)

scrapy 2.3 嵌套选择器

2021-06-02 16:15:57 更新

选择方法 (​.xpath()​ 或 ​.css()​ )返回同一类型选择器的列表,以便您也可以调用这些选择器的选择方法。下面是一个例子:

>>> links = response.xpath('//a[contains(@href, "image")]')
>>> links.getall()
['<a href="image1.html">Name: My image 1 <br><img src="image1_thumb.jpg"></a>',
 '<a href="image2.html">Name: My image 2 <br><img src="image2_thumb.jpg"></a>',
 '<a href="image3.html">Name: My image 3 <br><img src="image3_thumb.jpg"></a>',
 '<a href="image4.html">Name: My image 4 <br><img src="image4_thumb.jpg"></a>',
 '<a href="image5.html">Name: My image 5 <br><img src="image5_thumb.jpg"></a>']
>>> for index, link in enumerate(links):
...     href_xpath = link.xpath('@href').get()
...     img_xpath = link.xpath('img/@src').get()
...     print(f'Link number {index} points to url {href_xpath!r} and image {img_xpath!r}')
Link number 0 points to url 'image1.html' and image 'image1_thumb.jpg'
Link number 1 points to url 'image2.html' and image 'image2_thumb.jpg'
Link number 2 points to url 'image3.html' and image 'image3_thumb.jpg'
Link number 3 points to url 'image4.html' and image 'image4_thumb.jpg'
Link number 4 points to url 'image5.html' and image 'image5_thumb.jpg'